Ch5.6 #15
As before – all are similar so I will pick the harder one.
Givens
AB = CD
AB = 9(x-2)
CD = x + 3(x+5)
Therefore,
9(x-2) = x + 3(x+5)
Now multiply out and solve
9x – 18 = x + 3x + 15
9x – x – 3x = 15 + 18
5x = 33
x = 6.6
Now go back and find the lengths
AB = 9(x-2) = 9(6.6 – 2) = 41.4
CD = AB = 41.4
CE = x = 6.6
ED = 3(x+5) = 3(6.6+5) = 34.8