As before – all are similar so I will pick the harder one.
AB = CD
AB = 9(x-2)
CD = x + 3(x+5)
9(x-2) = x + 3(x+5)
Now multiply out and solve
9x – 18 = x + 3x + 15
9x – x – 3x = 15 + 18
5x = 33
x = 6.6
Now go back and find the lengths
AB = 9(x-2) = 9(6.6 – 2) = 41.4
CD = AB = 41.4
CE = x = 6.6
ED = 3(x+5) = 3(6.6+5) = 34.8
Now let’s look at Ch 5.6 #14.
Parts a-c are similar – so will do part c since the harder.
Area = x + 20 = (x-1)4 > I am just stating all things that are equal based on the given.
x+20 = (x-1)4
x+20 = 4x -4 > multiplied out
20 + 4 = 4x – x > moved similar items to same side
24 = 3x
x = 8
Now we know x, we have to find the sides (ALWAYS GO BACK AND MAKE SURE YOU KNOW WHAT WAS ASKED)
x -1 = 8 – 1 = 7
4 = 4
For problem 5.6, parts a-d are all pretty much the same. Here I will do part d) since a hair more complex. The steps the same for the others.
Since AB = CD, we can substitute the following
AB is x + 6(x+2)
CD is 2(x+10)
x + 6(x+2) = 2(x+10)
So to find the length of AB and CD, I need to figure out x. So solve the equation.
x + 6(x+2) = 2(x+10)
x + 6x + 12 = 2x + 20 – I just multiplied everything out
x + 6x – 2x = 20 – 12 > I moved all the x terms to the left and all the constants (numbers) to the right
5x = 8 > did the math
x = 8/5 = 1.6
Now I have x, but the problem asked for the lengths.
So now we can find the parts
AB = x + 6(x+2) = 1.6 + 6(1.6 + 2) = 1.6 + 6(3.6) = 23.2
AE = x = 1.6
EB = 6(x+2) = 21.6
CD = AB = 23.2
To do the others – follow the same process
This is an error in the Algebra Solutions Manual
In Algebra 1, chapter 5 lesson 1 problem 10x, the answer key says the answer is true for all positive integers. But isn’t it true for all integers? 1 to the power of x =1. If it is a negative power, it is still one, right?
Dr. Callahan Answer:
You are correct. Should be for all real numbers – not just integers. I tend to test these in a calculator to make sure though 😉
So that is incorrect in the Solutions manual.
Just for completeness sake – my goto math tool is Wolfram – so here is there answer.
Look for the following material or heading in the contents.
- Order of Operations
- Equations and inequalities
- Word problems (converting words into symbols)
- Real Numbers
- Distributive property
- Linear Equations (might be equations in one variable)
- Point-slope and or slope-intercept formulas
- Systems of linear equations (or simultaneous equations)
- Linear inequalities
- Absolute Values
- Scientific notation
- Quadratic equations
Notes for use: All the material on the above list needs to be covered in algebra. Instead of moving fast, the students should understand these concepts pretty well.
The test in the Teacher Guide for Test 2B on page 211 has an incorrect answer. The answer given in the solution manual is y=4x+1.
The correct answer is y = 4x-3.
Thanks Marybeth for catching this.
Angela’s son brought this error in the Earth cover Algebra I Solutions Manual to our attention. Thank you!
The problem (Ch3.4 #9) wording changed completely from the salamander cover to the Earth cover. However, the solution in the old and new solutions manuals is the same. In other words, both manuals have the solution to the salamander wording of the problem. The Earth solutions manual has the wrong solution to the Earth Ch3.4 #9 problem.
Angela’s son worked it perfectly and here is his correct solution to the Earth cover Algebra I Chapter 3.4 Set 1 #9 problem.
A question brought to us by Marybeth. Thank you!
In Jacob’s Elementary Algebra Chapter 1 Review Set I Question 14b page 51.
“What is the total number of atoms in x propane molecules as a sum?”
The Solutions Manual for Elementary Algebra on page 14 lists the answer as:
b) 3x + 5x
The “5” is a typo. The answer should be 3x + 8x.
3x carbon atoms plus 8x hydrogen atoms
Test shows: 3(x+1)^1/2=(x+7)^1/2 while the answer booklet shows: 3(x+1)^1/2=(x-7)^1/2.
The answer key is correct. For the test, please change the problem to 3(x+1)^1/2=(x-7)^1/2