For Chap 13, Lesson 6, #32, the basis for the answers is the figure for #6. If we look carefully at the grid, applying the Pythagorean Theorem gives
XY^2 = 2^2 + 2^2 = 8,
so XY = sqrt8 = 2sqrt2.
YZ^2 = 1^2 + 1^2 = 2,
so YZ =sqrt2.
Therefore XY = 2YZ.
Harold Jacobs
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